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A car braked with a constant deceleration of $ 16\;ft/s^2 $, producing skid marks measuring $ 200\;ft $ before coming to a stop. How fast was the car traveling when the brakes were first applied?

$$

80 \mathrm{ft} / \mathrm{s}

$$

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Campbell University

Oregon State University

Baylor University

Idaho State University

okay. We know the integral of acceleration is velocity, which we can write as this vivo means initial velocity. Therefore, we know the integral again is position. We can set 200 cause of positions. 200 feet, people to negative 82 scored post V O. T. Giving us via vote is eight t squared plus 200 over g. Therefore, we are V a t. We have v a t zero, which is negative. 16 Teeples vivo. Therefore, what we know we can do is substitute envy with 16 see and solved to get tea is plus or minus five. Obviously we can't have a negative amount of time. Right? Became a native five seconds. Their first gonna consider the positive five. So 16 times five is the question for V Evo which gives us 80 feet per second.